Q1 D of 42 Page 136

Let’s find G.C.D of the following algebraic expressions:

3a2b2c, 12a2b4c2, 9a5b4


factors of 3a2b2c=3×a×a×b×b×c


Factors of 12a2b4c2= 2×2×3×a×a×b×b×b×b×c×c


Factors of 9a5b4=3×3×a×a×a×a×a×b×b×b×b


GCD is the greatest common divisor, which is equal to the product of all the common divisors.


∴the GCD of 3a2b2c, 12a2b4c2, 9a5b4=3a2b2


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