Let’s find G.C.D of the following algebraic expression:

6x²-13xa + 6a², 6x² + 11xa-10a², 6x² + 2xa-4a²

Factors of 6x²-13xa + 6a²

=6x²-9xa-4xa + 6a²

=3x(2x-3a)-2a(2x-3a)

= (3x-2a)(2x-3a)

Factors of 6x² + 11xa-10a²

= 6x² + 15xa-4xa-10a²

=3x(2x + 5a)-2a(2x + 5a)

=(3x-2a)(2x + 5a)

Factors of 6x² + 2xa-4a²

=6x² + 6xa-4xa-4a²

=6x(x + a)-4a(x + a)

=(6x-4a)(x + a)

=2(3x-2a)(x + a)

GCD is the greatest common divisor, which is equal to the product of all the common divisors.

∴ the GCD of 6x²-13xa + 6a², 6x² + 11xa-10a², 6x² + 2xa-4a²is 3x-2a