Evaluate:
Let 
Put 
A(x-1)+B(x+2)=5x+1
Now put x-1=0
Therefore, x=1
A(0)+B(1+2)=5+1=6
B=2
Now put x+2=0
Therefore, x=-2
A(-2-1)+B(0)=5×(-2)+1
A=3
Now From equation (1) we get,
Therefore,
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