Evaluate:
Let 
Now putting, 
A(x2+1)+(Bx+C)(x-1)=3x+5
Putting x-1=0,
X=1
A(2)+B(0)=3+5=8
A=4
By equating the coefficient of x2 and constant term, A+B=0
4+B=0
B=-4
A-C=5
4-C=5
C=-1
From equation (1),we get,
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