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Let ![]()
Put ![]()
A(x+1)(x2+1)+B(x2+1)+(Cx+D)(x+1)2=1
Put x+1=0
X=-1
A(0)+B(1+1)+0=1
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By equating the coefficient of x2 and constant term, A+C=0
A+B+2C=0……(2)
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A+B+D=1
Solving (2) and (3),we get,

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