Evaluate:
Let 
Putting t=x4
dt=4x3dx
Now putting, 
A(t-1)+Bt=1
Now put t-1=0
Therefore, t=1
A(0)+B(1) =1
B=1
Now put t=0
A(0-1)+B(0)=1
A=-1
Now From equation (1) we get,
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