Evaluate:
Let 
Putting t=ex
dt=ex dx
Now putting, 
A(3+t)+B(2+t)=1
Now put t+2=0
Therefore, t=-2
A(3-2)+B(0)=1
A=1
Now put t+3=0
Therefore, t=-3
A(0)+B(2-3)=1
B=-1
Now From equation (1) we get,
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