Evaluate:
Let 
Now putting, 
Ax2+(Bx + C)(3x+8) = 5x+8
Putting 3x+8=0,
By equating the coefficient of x2 and constant term,
A+3B=0
8C=8
C=1
From equation (1), we get,
Putting x+2=0,
X=-2
A(-4)2+B(0)+C(0)=-6+1=-5
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