let 
dx = 
dx
Put t=sinx
dt=cosxdx
Putting 
A(1+t)2 +B(1-t)(1+t)+C(1+t)=t
Now Putting 1-t=0
t=1
A(0)+B(0)+C(1+1)=1
Now Putting 1+t=0
t=-1
A(2)2 +B(0)+C(0)=-1
By equating the coefficient of t2,we get,A-B=0
From equation(1),we get,
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