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let ![]()
Put t=sinx
dt=cosxdx
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Putting ![]()
A(1+t)(5-4t)+B(1-t)(5-4t)+C(1+t)(1-t)=1
Now Putting 1+t=0
t=-1
A(0)+B(2)(9)+C(0)=1
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Now Putting 1-t=0
t=1
A(2) +B(0)+C(0)=1
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Now Putting 5-4t=0
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From equation(1),we get,
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