Let 
Put 
A(x2+x+1)+(Bx+C)(x-1)=1
Now putting x-1=0
X=1
A(1+1+1)+0=1
By equating the coefficient of x2 and constant term, A+B=0
A-C=1
From the equation(1), we get,
Put t=x2+x+1
dt=(2x+1)dx
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