Evaluate:
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Let ![]()
Put t=x2
dt=2xdx
Now putting,![]()
A(t+1)+B(t-1) = t
Putting t+1=0,
t=-1
A(0)+B(-1-1)=-1
![]()
Putting t-1=0,
t=1
A(1+1)+B(0)=1
![]()
From equation(1),we get,
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