Evaluate:
Let 
Now putting, 
A(x-2)2+B(x+2)(x-2)+C(x+2)=3x+1
Putting x-2=0,
X=2
A(0)+B(0)+C(2+1)=3×2+1
Putting x+2=0,
X=-2
A(-4)2+B(0)+C(0)=-6+1=-5
By equation the coefficient of x2, we get, A+B=0
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