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15. Integration Using Partial Fractions
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Q31 of 168 Page 762

Evaluate:


Let


Now putting,


A(x-1)2+B(x-3)(x-1)+C(x-3)=x2+1


Putting x-1=0,


X=1


A(0)+B(0)+C(1-3)=1+1


C=-1


Putting x-3=0,


X=3


A(3-1)2+B(0)+C(0)=9+1


A(4)=10



Equating the coefficient of x2


A+B=1




From (i)



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Questions · 168
15. Integration Using Partial Fractions
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