Let 
Put 
A(x2+4)+(Bx+C)(2x+1) =17
Put 2x+1=0
A=4
By equating the coefficient of x2 and constant term,
A+2B=0
4+2B=0
B=-2
4A+C=17
4×4+C=17
C=1
From the equation(1), we get,
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