Q3 of 149 Page 14

If the points (2, 1) and (1,-2) are equidistant from the point (x, y), show that x + 3y = 0.

Distance from point (2, 1) = Distance from point (1, -2)



Square roots are cancelled, therefore






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1

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(ii) (a + b, b + c) and (a - b, c - b)

(iii) (a sin a, - b cos a) and (-a cos a, b sin a)

(iv) (a, 0) and (0, b)

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