Prove that (4, 3), (6, 4), (5, 6) and (3, 5) are the angular points of a square.
Let given points be A(4, 3), B(6, 4), C(5, 6) and D(3, 5).

By distance formula,
XY = ![]()
For AB,
AB = ![]()
= ![]()
=
units.
For BC,
BC = ![]()
= ![]()
=
units.
For CD,
CD =![]()
= ![]()
=
units.
For AD,
AD = ![]()
= ![]()
=
units.
Here, we can observe that □ABCD is a parallelogram.
Now,
For diagonal AC,
AC = ![]()
= ![]()
=
units.
For diagonal BD,
BD =![]()
= ![]()
=
units.
∴ AC = BD, which means diagonals are equal.
We know that quadrilateral in which all sides are equal and diagonals are equal, is a square.
∴□ABCD is a square.
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