A point P divides the line segment joining the points A (3, -5) and B (-4, 8) such that
. If P lies on the line x + y = 0, then find the value of k.
Here given points are A (3, -5) and B (-4, 8) .
Let point P be (x, y) which divides AB in ratio of k:1, also point P lies on line x + y = 0

By section formula,
x =
, y = ![]()
For point P on the line joined by the points A and B.
x =
, y = ![]()
Putting in given equation,
+
=0
∴-4k +3 +8k -5 = 0
∴ 4k = 2
∴ k = ![]()
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