If the mid-point of the line joining (3, 4) and (k, 7) is (x, y) and 2x + 2y + 1 = 0, find the value of k.
Let A(3, 4) and B(k, 7) and midpoint be C(x, y) which lies on the line 2x+2y+1 = 0

By midpoint formula,
x =
, y = ![]()
For point C(x, y),
x =
, y =
…(1)
Here, y =
,
Hence, substituting value of y in given equation of line,
2x + 2 ×
+ 1 = 0
∴ 2x = -12
∴ x = -6
Now substituting value of x in equation(1), we get.
x = ![]()
-6 = ![]()
∴ -12 = 3 + k
∴ k = -15
Hence, the value of k is -15.
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.