Q31 of 149 Page 14

Find the value of x such that where the coordinates of P, Q and R are (6,-1), (1, 3) and (x, 8) respectively.

Coordinates are P(6,-1), Q(1, 3) and R(x, 8)


Using distance formula =


⇒ PQ = QR



On squaring both sides, we get


=


=



On solving above equation, we get







Therefore x = -3, 5


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Prove that the points A (2, 3), B (-2, 2), C (-1, -2), and D (3, -1) are the vertices of a square ABCD.

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Find the point on x-axis which is equidistant from the points (-2, 5) and (2,-3).

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Prove that the points (0, 0), (5, 5) and (-5, 5) are the vertices of a right isosceles triangle.

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If the point P(x, y) is equidistant from the points A(5, 1) and B (1, 5), prove that x = y.