Q19 of 149 Page 14

Which point on y-axis is equidistant from (2, 3) and (-4, 1)?

Since the point is on y-axis, therefore coordinate of x-axis is zero.

Therefore the point is P(0, k) which is equidistance from A(2, 3) and B(- 4, 1)

PA = PB

On squaring both sides, we get

Therefore coordinate is (0, -1)

Prove that the points (- 2, 5), (0, 1) and (2, - 3) are collinear.

The coordinates of the point P are (-3, 2). Find the coordinates of the point Q which lies on the line joining P and origin such that OP = OQ.

The three vertices of a parallelogram are (3, 4), (3, 8) and (9, 8). Find the fourth vertex.

Find the circumcentre of the triangle whose vertices are (-2, -3), (- 1, 0), (7, - 6).