Q49 of 149 Page 14

If the point P (2, 2) is equidistant from the points A (-2, k) and B (-2k, -3), find k. Also, find the length of AP.

Coordinates of points are P(2, 2) A(-2, k) and B(-2k, -3)

Using distance formula =

⇒ PA = PB

On squaring both sides, we get

-1, -3

AP = = = 5 units

If A (3, y) is equidistant from points P (8, -3) and Q (7,6) , find the value of y and find the distance AQ.

If (0, - 3) and (0, 3) are the two vertices of an equilateral triangle, find the coordinates of its third vertex.

If the point A (0, 2) is equidistant from the points B (3, p) and C (p, 5) the length of AB.

If the point P (k -1, 2) is equidistant from the points A (3, k) and B (k,5), find the value of k.