Q51 of 149 Page 14

If the point P (k -1, 2) is equidistant from the points A (3, k) and B (k,5), find the value of k.

Coordinates of points are A(3, k), B(k, 5) and P(k-1, 2)


Using distance formula =


⇒ PA = PB



On squaring both sides, we get


=


=


= 1 + 9


= 0


= 0


= 0


= 0


= 1, 5


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