Find the lengths of the medians of a
ABC having vertices at A (5, 1), B (1, 5), and C(-3, -1).
Here given vertices are A (0,-1), B (2, 1) and C (0, 3) and let midpoints of BC, CA and AB be D,E and F respectively.

By midpoint formula.
x =
, y = ![]()
For midpoint D of side BC,
x =
, y = ![]()
x =
, y = ![]()
∴midpoint of side BC is D(-1, 2)
For midpoint E of side AB,
x =
, y = ![]()
x =
, y = ![]()
∴midpoint of side AB is E(1, 0)
For midpoint F of side CA,
x =
, y = ![]()
x =
, y = ![]()
∴midpoint of side CA is F(3, 3)
By distance formula,
XY = ![]()
For median AD,
AD = ![]()
= ![]()
=
units
For median BE,
BE = ![]()
= ![]()
= 5 units.
For median CF,
CF = ![]()
= ![]()
=
units
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