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7. Factorisation
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Q1 of 137 Page 99

Factories:

(i) 12x + 15


(ii) 14m – 21


(iii) 9n – 12n2

(i) 12x + 15


Taking 3 as common from the whole, we get,


12x + 15 = 3(4x + 5).


(ii) 14m – 21,


Taking 7 as common from the whole, we get,


14m – 21 = 7(2m – 3)


(iii) 9n – 12n2,


Taking 3n as common from the whole, we get,


9n – 12n2 = 3n (3 – 4n).


More from this chapter

All 137 →
2

Factories:

i. 16a2 – 24ab


ii. 15ab2 – 20a2b


iii. 12x2y3 – 21x3y2

3

Factories:

(i) 24x3 – 36x2y


(ii) 10x3 – 15x2


(iii) 36x3y – 60x2y3z

4

Factories:

i. 9x3 – 6x2 + 12x


ii. 8x3 – 72xy + 12x


iii. 18a3b3-27a2b3+36a3b2

5

Factories:

i. 14x3 + 21x4y – 28x2y2


ii. - 5 – 10t + 20t2

Questions · 137
7. Factorisation
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