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7. Factorisation
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Q6 of 137 Page 100

Factories:

9a2b2 – 25

We have,


9a2b2 – 25


= (3ab)2 – (5)2


By using the formula a2 – b2 = (a + b)(a – b)


We get,


9a2b2 – 25 = (3ab)2 – (5)2


= (3ab + 5)(3ab – 5)


More from this chapter

All 137 →
4

Factories:

4x2 – 9y2

5

Factories:

16a2 – 225b2

7

Factories:

16a2 – 144

8

Factories:

63a2 – 112b2

Questions · 137
7. Factorisation
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