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7. Factorisation
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Q40 of 137 Page 102

Factorize:

4n2 – 8n + 3

Given,


4n2 – 8n + 3


Now first find the numbers whose-


Sum = - 8 and


Product = 4 × 3 = 12


Required numbers are 6 and 2,


So we get;


4n2 – 8n + 3


= 4n2 – 2n – 6n + 3


= 2n(2n – 1) – 3(2n – 3)


= (2n – 1)(2n – 3)


More from this chapter

All 137 →
38

Factorize:

6x2 – 5x – 6

39

Factorize:

3m2 + 24m + 36

41

Factorize:

6x2 – 17x – 3

42

Factorize:

7x2 – 19x – 6

Questions · 137
7. Factorisation
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