Q30 of 137 Page 102

Factorize:

3y2 + 14y + 8

Given,


3y2 + 14y + 8


Now first find the numbers whose-


Sum = 14 and


Product = 3 × 8 = 24


Required numbers are 12 and 2,


So we get;


3y2 + 14y + 8 = 3y2 + 12y + 2y + 8


= 3y(y + 4) + 2(y + 4)


= (y + 4)(3y + 2)


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