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7. Factorisation
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Q24 of 137 Page 100

Factories:

25a2 – 4b2 + 28bc – 49c2

Given,


25a2 – 4b2 + 28bc – 49c2


= 25a2 – (4b2 – 28bc + 49c2)


By using the formula a2 – b2 = (a + b)(a – b)


We get,


25a2 – 4b2 + 28bc – 49c2 = 25a2 – (4b2 – 28bc + 49c2)


= (5a)2 – (2b – 7c)2


= {5a + (2b – 7c)}{5a – (2b – 7c)}


= (5a + 2b – 7c)(5a – 2b + 7c)


More from this chapter

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Factories:

x2 – y2 – 2y – 1

23

Factories:

25 – a2 – b2 – 2ab

25

Factories:

9a2 – b2 + 4b – 4

26

Factories:

100 – (x – 5)2

Questions · 137
7. Factorisation
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