Q1 of 157 Page 753

Find the area of ΔABC whose vertices are:

A(3, 8), B(–4, 2) and C(5, –1)


Area of triangle


= 1/2(x1(y2−y3) + x2(y3−y1) + x3(y1−y2))


= 1/2(3(2 + 1)–4(–1–8) + 5(8–2))


= 1/2(9 + 36 + 30)


= 1/2(75)


= 37.5 sq units


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