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16. Coordinate Geometry
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Q16 of 157 Page 753

For what value of y are the points P(1, 4), Q(3, y) and R(–3, 16) are collinear?


To show that the points are collinear, we show that the area of triangle is equilateral = 0


Δ = 0


Δ = 1/2{x1(y2−y3) + x2(y3−y1) + x3(y1−y2)}


⇒ Δ = 1/2{1(y–16) + 3 (16–4)–3 (4–y)} = 0


⇒ y–16 + 36–12 + 3y = 0


⇒ 8 + 4y = 0


⇒ 4y = –8


y = –2


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Find the value of x for which the points A(x, 2), B(–3, –4) and C(7, –5) are collinear.

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Find the value of y for which the points A(–3, 9), B(2, y) and C(4, –5) are collinear.

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Questions · 157
16. Coordinate Geometry
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