The point on x-axis which is equidistant from points A(-1, 0) and B(5, 0) is

⇒ For the point to be equidistant, the point has to be the midpoint of the line joining the points A and B.

⇒ If P(x, y) is the midpoint of the line joining AB then By Midpoint Formula we have,

⇒ and y

Finding x co-ordinate of midpoint:

⇒

⇒

⇒ x = 2

Finding y- co-ordinate of midpoint:

⇒

⇒ y = 0

Therefore the point which is equidistant from A and B is P(2,0).