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16. Coordinate Geometry
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Q13 of 157 Page 753

Show that the following points are collinear:

A(–5, 1), B(5, 5) and C(10, 7)

To show that the points are collinear, we show that the area of triangle is equilateral = 0


⇒ Δ = 1/2 {(x1(y2−y3) + x2(y3−y1) + x3(y1−y2))}


⇒ Δ = 1/2{–5(5– 7) + 5 (7–1) + 10 (1–5) }


⇒ Δ = 1/2{10 + 30–40}


⇒ Δ = 0


Hence collinear.


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For what value of k(k > 0) is the area of the triangle with vertices (–2,5) and (k, –4) and (2k + 1,10) equal to 53 square units?

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Questions · 157
16. Coordinate Geometry
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