Q1 of 157 Page 753

Find the area of ΔABC whose vertices are:

A(10, –6), B(2, 5) and C(–1, 3)


Area of triangle


= 1/2(x1(y2−y3) + x2(y3−y1) + x3(y1−y2))


= 1/2(10(5–3) + 2(3 + 6)–1(–6–5))


= 1/2(20 + 18 + 11)


= 1/2(49)


= 24.5 sq units


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