Q6 of 157 Page 760

The perimeter of the triangle with vertices (0, 4), (0, 0) and (3, 0) is

The perimeter is the addition of lengths of all sides.


Let the points be A = (0, 4), B = (0, 0) and C = (3, 0).


The distance between any two points P1(x1, y1) and P2(x2, y2) is given by the following formula:


⇒


⇒ Distance AB =


=


= 4


⇒ Distance BC =


=


= 3


⇒ Distance AC =


= √(9 + 16)


= √25


= 5


∴ Perimeter = 3 + 4 + 5


= 12


Therefore the perimeter of triangle is 12.

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