Q1 of 71 Page 58

Solve the following pairs of linear equations by the method of substitution:

multiplying 6 to L.H.S and R.H.S to the first equation to remove fraction

we get,


9x – 10y = –12 …[1]


multiplying 6 to L.H.S and R.H.S to the second equation to remove fraction


we get, 2x + 3y = 13


⇒ …[2]


Substituting eq[2] in eq[1]


⇒


⇒ 27x – 130 + 20x = –36


⇒ x = 2


Using this result in eq[2]



⇒ y = 3


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