Solve the following pairs of linear equations:
3x + y ≠ 0, 3x – y ≠ 0
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Putting these value in given equations, we get
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So, the given equations transforms into linear equation in two variables i.e.
4a + 4b = 3 … (i)
4a – 4b = 1 …..(ii)
Add (i) and (ii),
4a + 4b + 4a – 4b = 3 + 1
⇒ 8a = 4
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Putting above value in (i),
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⇒ 4b = 3 – 2
⇒ 4b = 1
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… (iii)
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…. (iv)
Add (iii) and (iv),
3x + y + 3x – y = 2 + 4
⇒ 6x = 6
⇒ x = 1
Putting the above value in (iii),
3(1) + y = 2
⇒ y = 3 – 2
⇒ y = 1
Couldn't generate an explanation.
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x ≠ 1, y ≠ 1
x > 0, y > 0