5 women and 2 men together can finish an embroidery work in 4 days, while 6 women and 3 men can finish it in 3 days. Find the time taken by 1 woman alone to finish the work. Also find the time taken by 1 man alone to finish the work.
Let W and M represent the work done by a woman and a man respectively.
It is given that 5 women and 2 men can do the work in 4 days.
So, work done by 5 women and 2 men in a day will be ![]()
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⇒ 20W + 8M = 1 …. (i)
Also,
It is given that 6 women and 3 men can do the same work in 3 days.
So, work done by 6 women and 3 men in a day will be ![]()
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⇒ 18W + 9M = 1 …. (ii)
From (i) and (ii) equation,
20W + 8M = 18W + 9M
⇒ 2W = M
This means that the work done by 2 women in a day is equal to the work done by a man in a day. Substituting the value of M in (i) equation, we get
20W + 8M = 1
⇒ 20W + 8× 2W = 1
⇒ (20 + 16) W = 1
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So, a woman do
work in a day.
This means a woman will finish the work in 36 days if working alone.
Now, put the value of W in (ii),
18W + 9M = 1
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So, a man do
work in a day.
This means a man will finish the work in 18 days if working alone.
Couldn't generate an explanation.
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3x + y ≠ 0, 3x – y ≠ 0
x > 0, y > 0