The sum of the digits of two–digit number is 3. The number obtained by interchanging the digits is 9 less than the original number. Find the original number.
Let the digit at 10s place y and digit at one’s place be x.
∴ 10y + x = The number
Now if we interchange the digits we get a number that is 9 less than the original number.
interchanged number = 10x + y
⇒ 10x + y = 10y + x – 9
⇒ 9x – 9y + 9 = 0
⇒ x – y + 1 = 0 …[1]
and the sum of digits is 3
⇒ x + y = 3 eq[2]
adding eq[1] and …[2]
2x = 2
⇒ x = 1
From eq[1]
x – y + 1 = 0
⇒ y = 2
∴ the original number is 21
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.