Q4 of 71 Page 62

The sum of the digits of two–digit number is 3. The number obtained by interchanging the digits is 9 less than the original number. Find the original number.

Let the digit at 10s place y and digit at one’s place be x.

10y + x = The number


Now if we interchange the digits we get a number that is 9 less than the original number.


interchanged number = 10x + y


10x + y = 10y + x – 9


9x – 9y + 9 = 0


x – y + 1 = 0 …[1]


and the sum of digits is 3


x + y = 3 eq[2]


adding eq[1] and …[2]


2x = 2


x = 1


From eq[1]


x – y + 1 = 0


y = 2


the original number is 21


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