Q1 of 71 Page 68

Solve the following pairs of linear equations:

x ≠ 0, y ≠ 0



Putting these value in given equations, we get




So, the given equations transforms into linear equation in two variables i.e.


15a + 4b = 42 … (i)


3a + 2b = 12 …..(ii)


Multiply equation (ii) by 5, so


15a + 4b = 42 … (iii)


15a + 10b = 60 …..(ii)


Subtract (iii) from (ii),


15a + 10b – 15a – 4b = 60 – 42


⇒ 6b = 18


⇒ b = 3


Putting above value in (ii),


3a + 2× 3 = 12


⇒ 3a = 12 – 6


⇒ 3a = 6


⇒ a = 2



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