The difference between two natural numbers is 6. Adding 10 to the twice of the larger number, we get 2 less than 3 times of the smaller number. Find these numbers.
Let the two natural numbers be x and y such that x is the larger number and y is the smaller number.
According to the question,
x – y = 6
and 2x + 10 = 3y – 2
⇒ x – y – 6 = 0 …(i)
And 2x – 3y + 12 = 0 ..(ii)
Multiply (i) by 2,
2x – 2y – 12 = 0 .. (iii)
2x – 3y + 12 = 0 ..(ii)
Subtract (iii) from (ii),
2x – 3y + 12 – 2x + 2y + 12 = 0
⇒ – y + 24 = 0
⇒ y = 24
Putting this value in (i),
x – 24 – 6 = 0
⇒ x = 30
So the numbers are 30 and 24.
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and
x ≠ 1, y ≠ 2