Q1 of 71 Page 62

Solve the following pair of linear equations by elimination method:

5ax + 6by = 28; 3ax + 4by = 18

Multiply the first equation by 2 and the second equation by 3.


⇒ 10ax + 12by = 56 …[1]


⇒ 9ax + 12by = 54 …[2]


on subtracting eq[2] from eq [1]


ax = 2


⇒ x =


by x = and 3ax + 4by = 18


3a() + 4by = 18


we get


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