Q10 of 71 Page 68

The solution set of x — 3y = 1 and 3x + y = 3 is

Given: x — 3y = 1…(i)


3x + y = 3 …(ii)


Multiply (i) by 3,


3x – 9y = 3 ..(iii)


3x + y = 3…(ii)


Subtract (ii) from (iii),


3x – 9y – 3x – y = 3 – 3


⇒ – 10y = 0


⇒ y = 0


Putting this in (i),


x – 0 = 1


⇒ x = 1


So, the solution set will be {1, 0}.

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