The sum of two numbers is 70 and their difference is 6. Find these numbers by cross – multiplication method.
Let the two numbers be x and y.
According to the question,
x + y = 70 and x – y = 6
⇒ x + y – 70 = 0 and x –y – 6 = 0
On comparing with a1x + b1y + c1 = 0 and a2x + b2y + c2 = 0we get,
a1 = 1, b1 = 1, c1 = – 70; a2 = 1, b2 = – 1, c2 = – 6
Applying cross multiplication method which says,
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Putting the given values in the above equation we get,

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Similarly,
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∴The solution of the pair of equations is (38, 32).
So, the required numbers will be 38 and 32.
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