Solve the following pairs of linear equations:
2x + 3y = 2xy, 6x + 12y = 7xy
Given: 2x + 3y = 2xy, 6x + 12y = 7xy
One of the solutions for given pair of equations will be x = 0 and y = 0
But let us find out some other solution as well.
Divide both the equations with xy,
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Putting these value in given equations, we get
2b + 3a = 2, 6b + 12a = 7
So, the given equations transforms into linear equation in two variables i.e.
2b + 3a = 2… (i)
6b + 12a = 7….. (ii)
Multiply equation (i) by 3, so
6b + 9a = 6 … (iii)
6b + 12a = 7….. (ii)
Subtract (iii) from (ii),
6b + 12a – 6b – 9a = 7 – 6
⇒ 3a = 1
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Putting above value in (ii),
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⇒ 2b = 2 – 1
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Couldn't generate an explanation.
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the sum of the measures of
x ≠ 0, y ≠ 0
x ≠ 1, y ≠ 1
3x + y ≠ 0, 3x – y ≠ 0