Q1 of 71 Page 62

Solve the following pair of linear equations by elimination method:

multiply 15 to the first equation to remove fraction

we get, 3x – 5y = 4 …[1]


Now let’s, multiply 18 to the second equation to remove fraction


we get, 9x – 2y = 7 …[2]


Now, let’s find eq[2] – eq[1] × 3


⇒ 9x – 2y – 3(3x – 5y) = 7 – 4×3


⇒


Now if we put this result in eq[1]



⇒ 39x = 27


⇒


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