Q4 of 70 Page 120

Δ PQR ~ ΔDEF for the correspondence PQR ↔ EDF. If PQ + QR = 15, DE + DF = 10 and PR = 6, find EF.

Given, PQR and DEF are similar for the correspondence PQR EDF.

PQ + QR = 15 and DE + DF = 10


PR = 6


If the correspondence PQRDEF is a similarity.


Hence,


And


From these above two equations




EF


EF = 4


More from this chapter

All 70 →
2

For ΔPQR and ΔXYZ, the correspondence PQR ↔ YZX is a similarity. m∠P = 2m∠Q and m∠X = 120. Find m∠Y.

 3

The correspondence ABC ↔ PQR between Δ ABC and Δ PQR is a similarity. AB : PQ = 4 : 5. If AC = 6, then find PR. If QR = 15, then find BC.

 5

In ΔABC and ΔPQR, ABC ↔ QPR is a similarity. The perimeter of AABC is 15 and perimeter of ΔPQR is 27. If BC = 7 and QR = 9, find PR and AC.

 6

In ΔXYZ ~ ΔDEF consider the correspondence XYZ ↔ EDF.

If find and .