In □ABCD, M and N are the mid-points of
and
. If
∥
prove that
∥![]()

Given: In □ ABCD, M and N are the mid points of
and
and
∥ ![]()
To Prove:
∥ ![]()
Construction:- extend
towards D and
towards C to intersect each other at P ( ∵ AB > CD)
Proof:- M is the mid-point of ![]()
∴ DA = 2 DM …………1
Similarly, N is the mid-point of ![]()
∴ CB = 2 CN…………..eq(2)
In Δ PAB ,
∥ ![]()
∴ ![]()
( ∵ If a line ∥ to one side of a Δ intersects the other two sides of the Δ in distinct points, the segments of the other sides of the Δ in the same half plane of the line are proportional to the corresponding sides of the Δ)
∴
(from 1 and 2)
∴![]()
In Δ PMN, P-D-M , P-C-N and
![]()
And ![]()
∴
∥ ![]()
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