The bisector of ∠P in ΔPQR intersects
in D. If QD: RD = 4 : 7 and PR = 14, then PQ = ………..
We have

Given: PD is the bisector of ∠P.
QD:RD = 4:7
PR = 14
To find: PQ = ?
In ∆PQR, the bisector of P intersects the line QR at D. By property of triangles,
⇒ ![]()
⇒ ![]()
⇒ ![]()
⇒ PQ = 2 × 4
⇒ PQ = 8
Thus, option (a) is correct.
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