In ΔXYZ, the bisector of ∠Y intersects
in P.
(1) If XP : PZ = 4 : 5 and YZ = 6.5, find XY.
(2) if XY : YZ = 2 : 3 and XP = 3.8, find PZ and ZX.
Given, XP : PZ = 4 : 5
XY : YZ = 2 : 3

In ∆XYZ, the bisector of angle Y intersects ZX in P.
(1) ∴ ![]()
![]()
XY = ![]()
XY = 5.2
(2) ![]()
![]()
PZ = ![]()
PZ = 5.7
ZX = PZ + XP
ZX = 5.7 + 3.8
ZX = 9.5
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